Please refer to Polynomials MCQ Questions Class 9 Mathematics below. These MCQ questions for Class 9 Mathematics with answers have been designed as per the latest NCERT, CBSE books, and syllabus issued for the current academic year. These objective questions for Polynomials will help you to prepare for the exams and get more marks.
Polynomials MCQ Questions Class 9 Mathematics
Please see solved MCQ Questions for Polynomials in Class 9 Mathematics. All questions and answers have been prepared by expert faculty of standard 9 based on the latest examination guidelines.
MCQ Questions Class 9 Mathematics Polynomials
Question. (x + y)3 – (x – y)3 – 6y(x2 – y2 ) =
(a) y3
(b) 2y3
(c) 4y3
(d) 8y3
Answer
D
Question. Factorise: x2+ (a + b + c)x + ab + bc
(a) (x + a)(x + b + c)
(b) (x + a)(x + a + c)
(c) (x + b)(x + a + c)
(d) (x + b)(x + b + c)
Answer
C
Question. If p(x) = x160 + 2x141 + k and p(–1) = 0, then the value of k is
(a) 1
(b) – 3
(c) 2
(d) – 2
Answer
A
Question. If a3 + b3 + c3 = 3abc, then a2 / bc + b2 / ca + c2 / ab =
(a) 0
(b) 1
(c) – 1
(d) 3
Answer
D
Question. If x = –2 and x2+ y2 + 3xy = –5, then find y.
(a) –2
(b) 3
(c) – 4
(d) 9
Answer
B
Question. The factors of x3 + 9x2 + 23x + 15 are
(a) (x + 1), (x + 3), (x + 5)
(b) (x + 1), (x + 3), (x – 5)
(c) (x + 1), (x – 3), (x – 5)
(d) (x – 1), (x – 3), (x – 5)
Answer
A
Question. The value of (369)2 – (368)2 is
(a) 12
(b) 81
(c) 37
(d) 737
Answer
D
Question. If p(y) = y2 – y + 1, then find the value of p(0) – p(1).
(a) 1
(b) 3
(c) 0
(d) 2
Answer
C
Question. Factors of polynomial 12x2 + 7x + 1 are
(a) (3x – 1)(4x + 1)
(b) (3x – 1)(4x – 1)
(c) (4x – 1)(3x– 1)
(d) (4x + 1)(3x + 1)
Answer
D
Question. If a + b + c = 13 and ab + bc + ca = 84, then find the value of a2 + b2 + c2.
(a) 1
(b) 2
(c) 3
(d) 4
Answer
A
Question. One of the zeroes of the polynomial 2x2 + 7x – 4 is
(a) 2
(b) 1/2
(c) − 1/2
(d) – 2
Answer
B
Question. The value of (9)3 + (– 3)3 is
(a) – 81
(b) 54
(c) 164
(d) 702
Answer
D
Question. Simplify : x3 – 4 – x + 4x2 / x2 + 3x – 4
(a) 4 + x
(b) 2 + x
(c) 1 – x
(d) x + 1
Answer
D
Question. If p(x) = x51 + 51, then value of p(–1) is
(a) 0
(b) 1
(c) 49
(d) 50
Answer
D
Question. Using algebraic identity, find the value of 209 × 191.
(a) 39851
(b) 39919
(c) 39961
(d) 38951
Answer
B
Question. The degree of the polynomial (y3 – 3)(y2+ 8) is
(a) 2
(b) 3
(c) 0
(d) 5
Answer
D
Question. The coefficient of the highest power of x in the polynomial 3x3 – 4x4 + 5x2 – 2x5 + 3 is
(a) 2
(b) – 4
(c) 3
(d) –2
Answer
D
Assertion & Reasoning Based MCQs
(a) Assertion and Reason both are correct statements and Reason is the correct explanation of Assertion.
(b) Assertion and Reason both are correct statements but Reason is not the correct explanation of Assertion.
(c) Assertion is correct statement but Reason is wrong statement.
(d) Assertion is wrong statement but Reason is correct statement.
Question. Assertion : The degree of the polynomial (x2 – 2)(x – 3)(x + 4) is 3.
Reason : A polynomial of degree 3 is called a cubic polynomial.
Answer
D
Question. Assertion : 3x2 + x – 1 = (x + 1) (3x – 2) + 1.
Reason : To factorise ax2 + bx + c, write b as sum of two numbers whose product is ac.
Answer
A
Question. Assertion : The value of (–27)3 + (–9)3 is –20412.
Reason : If a + b = 0, then a3 + b3 + c3 = 0
Answer
C
Question. Assertion : If 2x2 – 32 is the volume of a cuboid, then length of cuboid can be x – 8.
Reason : Volume of a cuboid = l × b × h.
Answer
D
Question. Assertion : The expression 3×4 – 4x3/2 + x2 = 2 is not a polynomial because the term – 4x3/2 contains a rational power of x.
Reason : The highest exponent in various terms of an algebraic expression in one variable is called its degree.
Answer
B
Question. Assertion : If x = 3/2 is a zero of polynomial 2x2 + kx – 12, then k = 5.
Reason : If x = a is zero of a polynomial f(x), then f(a) = 0.
Answer
A
Question. Assertion : –7 is a constant polynomial.
Reason : Degree of a constant polynomial is zero.
Answer
A
Question. Assertion : The value of 593 × 607 is 359951.
Reason : (a + b) (a – b) = a2 – b2
Answer
A
Fill in the blanks:
Question. If (x – 1) is a factor of x2 + x + k, then value of k is ______.
Answer
–2
Question. Coefficient of x2 in the polynomial π/4x2 – 3x + 4 is ______.
Answer
π/4
Question. Zero of the polynomial p(x) = 2x + 3 is ______.
Answer
– 3/2
Question. If x/y + y/x = –1 , (x ≠ 0, y ≠ 0), then the value of x3 – y3 is______.
Answer
0
Question. If x –1/x = 3 , then value of x3 – 1/ x3 s _____ .
Answer
33
Question. Degree of a linear polynomial is______ .
Answer
1
True /False:
Question. If p(x) = x2+ 3x + 2, then p(1) + p(2) + p(0) is 18.
Answer
False
Question. Degree of the polynomial 2 – x2 – 3x3 + 2x7 is 7.
Answer
True
Question. (x + 1) is a factor of x140 + 2x141 + 2.
Answer
False
Question. Zeroes of a polynomial 3(x – 2) (x + 3) are 2 and 3.
Answer
False
Question. Degree of the zero polynomial is zero.
Answer
False
Question. Zero of a zero polynomial is any real number.
Answer
True
Question. (x – 3) is a factor of 2x3 – 5x2 + 2x – 18.
Answer
False
Case Based MCQs
Read the following passage and answer the questions.
Ankur and Ranjan start a new business together. The amount invested by both partners together is given by the polynomial p(x) = 4x2 + 12x + 5, which is the product of their individual shares.
Question. Total amount invested by both, if x = 1000 is
(a) Rs 301506
(b) Rs 370561
(c) Rs 4012005
(d) Rs 490621
Answer
C
Question. The shares of Ankur and Ranjan invested individually are
(a) Rs (2x + 1), Rs (2x + 5)
(b) Rs (2x + 3), Rs (x + 1)
(c) Rs (x + 1), Rs (x + 3)
(d) None of these
Answer
A
Question. Find the value of x, if the total amount invested is equal to 0.
(a) –1/2
(b) –5/2
(c) Both (a) and (b)
(d) None of these
Answer
C
Question. Coefficient of x2 in the given polynomial is
(a) 2
(b) 3
(c) 4
(d) 12
Answer
C
Question. Name the polynomial of amounts invested by each partner.
(a) Cubic
(b) Quadratic
(c) Linear
(d) None of these
Answer
C