VBQs Coordination Compounds Class 12 Chemistry with Coordination Compounds has been provided below for standard students. We have provided chapter wise VBQ for Class 12 Chemistry with Coordination Compounds. The following Coordination Compounds Class 12 Chemistry value based questions with answers will come in your exams. Students should understand the concepts and learn the solved cased based VBQs provided below. This will help you to get better marks in class 12 examinations.
Coordination Compounds VBQs Class 12 Chemistry
Question. Which of the following does not show optical isomerism?
(a) [Co(NH3)3Cl3]0
(b) [Co (en) Cl2 (NH3)2]+
(c) [Co (en)3]3+
(d) [Co (en)2Cl2]+ (en = ethylenediamine)
Answer
A
Question. Which of the following is the correct name of compound.
[Co(NH3)4(H2O)Cl]Cl2
(a) Tetraamineaqua chloride cobalt (III) chloride
(b) Tetraamineaqua chlorido cobalt (II) chloride
(c) Tetraamineaqua chloride cobalt (II) chloride
(d) Tetraamineaqua chlorido cobalt (III) chloride
Answer
D
Question. Which one of the following complex ions has geometrical isomers ?
(a) [Ni(NH3)5Br]+
(b) [Co(NH3)2(en)2]3+
(c) [Cr(NH3)4(en)2]3+
(d) [Co(en)3]3+
(en = ethylenediamine)
Answer
B
Question. Which of the following will give maximum number of isomers?
(a) [Ni(C2O4) (en)2]2–
(b) [Ni(en) (NH3)4]2+
(c) [Cr(SCN)2 (NH3)4]+
(d) [Co(NH3)4 Cl2]
Answer
C
Question. Which of the following coordination compounds would exhibit optical isomerism?
(a) pentamminenitrocobalt(III) iodide
(b) diamminedichloroplatinum(II)
(c) trans-dicyanobis (ethylenediamine) chromium (III) chloride
(d) tris-(ethylendiamine) cobalt (III) bromide
Answer
D
Question. The geometry of Ni(CO)4 and Ni(PPh3)2Cl2 are
(a) both square planar
(b) tetrahedral and square planar
(c) both tetrahedral
(d) None of these
Answer
C
Question. The type of isomerism present in Pentaminenitrochromium (III) chloride is
(a) optical
(b) linkage
(c) ionisation
(d) polymerisation.
Answer
B
Question. Which of the following type of isomerism is shown by given complex compound?
(a) Facial
(b) Meridional
(c) Cis
(d) Both b and c
Answer
B
Question. Which of the following ions can exhibit optical isomerism–
(a) [Co(NH3)4Cl2]+
(b) [Co(NH3)2Cl4]–
(c) Cis-[Co(en)2Cl2]+
(d) trans-[Co(en)2Cl2]+
Answer
C
Question. Which would exhibit co-ordination isomerism
(a) [Cr(NH3)6][Co(CN)6]
(b) [Co(en)2Cl2]
(c) [Cr(NH3)6]Cl3
(d) [Cr(en)2Cl2]+
Answer
A
Question. [Co(NH3)5NO2]Cl2 and [Co(NH3)5(ONO)]Cl2 are related to each other as
(a) geometrical isomers
(b) optical isomers
(c) linkage isomers
(d) coordination isomers
Answer
C
Question. The complexes [Co(NH3)6] [Cr(CN)6] and [Cr(NH3)6]
[Co(CN)6] are the examples of which type of isomerism?
(a) Linkage isomerism
(b) Ionization isomerism
(c) Coordination isomerism
(d) Geometrical isomerism
Answer
C
Question. The complex, [Pt(py)(NH3)BrCl] will have how many geometrical isomers ?
(a) 3
(b) 4
(c) 0
(d) 2
Answer
A
Question. Which one of the following will show paramagnetism corresponding to 2 unpaired electrons?
(Atomic numbers : Ni = 28, Fe = 26)
(a) [FeF6]3–
(b) [NiCl4]2–
(c) [Fe(CN)6]3–
(d) [Ni(CN)4]2–
Answer
B
Question. Which of the following has a square planar geometry?
(a) [PtCl4]2–
(b) [CoCl4]2–
(c) [FeCl4]2–
(d) [NiCl4]2–
(At. nos.: Fe = 26, Co = 27, Ni = 28, Pt = 78)
Answer
A
Question. The type of isomerism present in nitropentaamminechromium (III) chloride is
(a) optical
(b) linkage
(c) ionization
(d) polymerization
Answer
B
Question. Which one of the following has an optical isomer?
(a) [Zn(en) (NH3)2]2+
(b) [Co(en)3]3+
(c) [Co(H2O)4(en)]3+
(d) [Zn(en)2]2+
(en = ethylenediamine)
Answer
B
Question. Which one of the following cyano complexes would exhibit the lowest value of paramagnetic behaviour ?
(a) [Co(CN)6 ]3-
(b) [Fe(CN)6 ]3-
(c) [Mn(CN)6 ]3-
(d) [Cr(CN)6 ]3-
(At. Nos : Cr = 24, Mn = 25, Fe = 26, Co = 27)
Answer
A
Question. IUPAC name of Na3[Co(ONO)6] is
(a) Sodium cobaltinitrite
(b) Sodium hexanitrito cobaltate (III)
(c) Sodium hexanitrocobalt (III)
(d) Sodium hexanitritocobaltate (II)
Answer
B
Question. Change in composition of co-ordination sphere yields which type of isomers
(a) optical
(b) geometrical
(c) ionisation
(d) None of these
Answer
C
Question. Isomerism exhibited by [Cr(NH3)2(H2O)2Cl2]+ are –
(a) ionization, optical
(b) hydrate, optical
(c) geometrical, optical
(d) coordinate, geometrical
Answer
C
Question. Which of the following complexes exhibits the highest paramagnetic behaviour ?
(a) [V(gly)2(OH)2(NH3)2]+
(b) [Fe(en)(bpy)(NH3)2]2+
(c) [Co(ox)2(OH)2]2–
(d) [Ti(NH3)6]3+
where gly = glycine, en = ethylenediamine and bpy = bipyridyl moities)
(At.nosTi = 22, V = 23, Fe = 26, Co = 27)
Answer
B
Question. Which of the following complex will show geometrical as well as optical isomerism (en=ethylenediammine)
(a) Pt(NH3)2Cl2
(b) [Pt(NH3)Cl4]
(c) [Pt(en)3]4+
(d) [Pt(en)2Cl2]
Answer
D
Question. Which of the following compounds shows optical isomerism?
(a) [Co(CN)6 ] 3-
(b) [Cr(C2O4 )3 ]3-
(c) [ZnCl4 ]2-
(d) [Cu(NH3 )4 ]2+
Answer
B
Question. The number of geometrical isomers from [Co(NH3)3(NO2)3] is
(a) 2
(b) 3
(c) 4
(d) 0
Answer
A
Question. Which one of the following octahedral complexes will not show geometric isomerism? (A and B are monodentate ligands)
(a) [MA5B]
(b) [MA2B4]
(c) [MA3B3]
(d) [MA4B2]
Answer
A
Question. The number of unpaired electrons in the complex [Cr(NH3)6]Br3 is (Atomic number Cr = 24)
(a) 4
(b) 1
(c) 2
(d) 3
Answer
D
Question. For the square planar complex [M (a) (b) (c) (d)] (where M = central metal and a, b, c and d are monodentate ligands), the number of possible geometrical isomers are
(a) 1
(b) 2
(c) 3
(d) 4
Answer
D
Question. Which of the following will exhibit optical isomerism ?
(a) [Cr(en) (H2O)4]3+
(b) [Cr(en)3]3+
(c) trans-[Cr(en)(Cl2)(NH3)2]+
(d) [Cr(NH3)6]3+
Answer
B
Question. Coordination isomerism is caused by the interchange of ligands between the
(a) cis and trans structure
(b) complex cation and complex anion
(c) inner sphere and outer sphere
(d) low oxidation and higher oxidation states
Answer
B
Question. The ionisation isomer of [Cr(H2O)4Cl(NO2)]Cl is
(a) [Cr(H2O)4(O2N)]Cl2
(b) [Cr(H2O)4Cl2](NO2)
(c) [Cr(H2O)4Cl(ONO)]Cl
(d) [Cr(H2O)4Cl2(NO2)].H2O
Answer
B
Question. The compounds [PtCl2(NH3)4]Br2 and [PtBr2(NH3)4]Cl2 constitutes a pair of
(a) coordination isomers
(b) linkage isomers
(c) ionization isomers
(d) optical isomers
Answer
C
Question. Which one of the following will not show geometrical isomerism ?
(a) [Cr(NH3)4Cl2]Cl
(b) [Co(en)2Cl2]Cl
(c) [Co(NH3)5NO2]Cl2
(d) [Pt(NH3)2Cl2 ]
Answer
C
Question. CN– is a strong field ligand. This is due to the fact that
(a) it carries negative charge
(b) it is a pseudohalide
(c) it can accept electrons from metal species
(d) it forms high spin complexes with metal species
Answer
B
Question. The compound which is not coloured is
(a) K4[Fe(CN)6 ]
(b) K3[Fe(CN)6 ]
(c) Na2 [CdCl4 ]
(d) Na2[CuCl4 ]
Answer
C
Question. The number of isomers exhibited by [Cr(NH3)3Cl3] is
(a) 2
(b) 3
(c) 4
(d) 5
Answer
D
Question. The number of geometrical isomers for [Pt(NH3)2Cl2] is
(a) 2
(b) 1
(c) 3
(d) 4
Answer
A
Question. Due to the presence of ambidentate ligands coordination compounds show isomerism. Palladium complexes of the type [Pd(C6H5)2(SCN)2] and [Pd(C6H5)2(NCS)2] are
(a) linkage isomers
(b) coordination isomers
(c) ionisation isomers
(d) geometrical isomers
Answer
A
Question. Which of the following facts about the complex [Cr(NH3)6]Cl3 is wrong?
(a) The complex involves d2sp3 hybridisation and is octahedral in shape.
(b) The complex is paramagnetic.
(c) The complex is an outer orbital complex
(d) The complex gives white precipitate with silver nitrate solution.
Answer
C
Question. Which of the following will give maximum number of isomers?
(a) [Co(NH3)4Cl2]
(b) [Ni(en)(NH3)4]2+
(c) [Ni(C2O4)(en)2]
(d) [Cr(SCN)2(NH3)4]2+
Answer
D
Question. Which of the following statements is correct ? (Atomic number of Ni = 28)
(a) Ni(CO)4 is diamagnetic and [NiCl4]2– and [Ni(CN)4]2– are paramagnetic
(b) Ni(CO)4 and [Ni(CN)4]2– are diamagnetic and [NiCl4]2– is paramagnetic
(c) Ni(CO)4 and [NiCl4]2–are diamagnetic and [Ni(CN)4]2– is paramagnetic
(d) [NiCl4]2– and [Ni(CN)4]2– are diamagnetic and Ni(CO)4 is paramagnetic
Answer
B
Question. Which of the following species represent the example of dsp2 – hybridisation ?
(a) [Fe(CN)6]3–
(b) [Ni(CN)4]2–
(c) [Ag(CN)2]–
(d) [Co(CN)6]3–
Answer
B
Question. Atomic number of Cr and Fe are respectively 25 and 26,which of the following is paramagnetic?
(a) [Cr(CO)6]
(b) [Fe(CO)5]
(c) [Fe(CN)6]–4
(d) [Cr(NH3)6]+3
Answer
D
Question. Which of the following pairs represent linkage isomers?
(a) [Pd(PPh3)2(NCS)2] and [Pd ( PPh3)2 (SCN)2]
(b) [Co(NH3)5NO3] SO4 and [Co(NH3)5SO4]NO3
(c) [PtCl2(NH3)4] Br2 and [Pt Br2 (NH3)4] Cl2
(d) [Cu(NH3)4][Pt Cl4] and [Pt(NH3)4][CuCl4]
Answer
A
Question. [Sc(H2O)6]3+ ion is :
(a) colourless and diamagnetic
(b) coloured and octahedral
(c) colourless and paramagnetic
(d) coloured and paramagnetic
Answer
A
Question. Which has maximum paramagnetic nature ?
(a) [Mn(H2O)6 ]2+
(b) [Cu(NH3)4 ]2+
(c) [Fe(CN)6 ]4-
(d) [Cu(H2O)4 ]2+
Answer
A
Question. What kind of isomerism exists between [Cr(H2O)6 ]Cl3 (violet) and [Cr(H2O)5Cl]Cl2.H2O (greyish-green) ?
(a) linkage isomerism
(b) solvate isomerism
(c) ionisation isomerism
(d) coordination isomerism
Answer
B
Question. Type of isomerism which exists between [Pd(C6H5)2(SCN)2] and [Pd(C6H5)2(NCS)2] is :
(a) Linkage isomerism
(b) Coordination isomerism
(c) Ionisation isomerism
(d) Solvate isomerism
Answer
A
Question. The IUPAC name of K3[Ir(C2O4)3] is
(a) potassium trioxalatoiridium (III)
(b) potassium trioxalatoiridate (III)
(c) potassium tris (oxalato) iridium (III)
(d) potassium tris (oxalato) iridate (III)
Answer
B
Question. Consider the following coordination compounds.
(i) [Pt(NH3)4Cl2]Br2
(ii) [Pt(NH3)4Br2]Cl2
(iii) [Co(NH3)4Cl2]NO2
Which of the following observations is correct?
(a) (i) will give a pale yellow and (ii) will give a white precipitate with AgNO3 solution.
(b) (iii) will give a white precipitate with AgNO3 solution.
(c) (i), (ii) and (iii) will give white precipitate with AgNO3 solution.
(d) None of the above coordination compounds will give white precipitate with AgNO3 solution.
Answer
A
Question. Which of the following is not correctly matched?
(a) Coordination compound containing cationic complex ion : [Fe(H2O)2(C2O4)2]2SO4
(b) Coordination compound containing anionic complex ion : [Ag(NH3)2]Cl
(c) Non-ionic coordination compound : [Co(NO2)3(NH3)3]
(d) Coordination compound containing cationic and anionic complex ion : [Pt(NH3)4] [CuCl4]
Answer
B
Question. Which of the following statements is correct about [Co(H2O)6]2+ complex?
Answer
A
Question. Which of the following rules is not correct regarding IUPAC nomenclature of complex ions?
(a) Cation is named first and then anion.
(b) In coordination sphere, the ligands are named alphabetically.
(c) Positively charged ligands have suffix ‘ate’.
(d) More than one ligand of a particular type are indicated by using di, tri, tetra, etc.
Answer
C
Question. Low spin tetrahedral complexes are not formed because
(a) for tetrahedral complexes, the CFSE is lower than pairing energy
(b) for tetrahedral complexes, the CFSE is higher than pairing energy
(c) electrons do not go to eg in case of tetrahedral complexes
(d) tetrahedral complexes are formed by weak field ligands only.
Answer
A
Question. Which of the following sets of examples and geometry of the compounds is not correct?
(a) Octahedral – [Co(NH3)6]3+, [Fe(CN)6]3–
(b) Square planar – [Ni(CN)4]2–, [Cu(NH3)4]2+
(c) Tetrahedral – [Ni(CO)4], [ZnCl4]2–
(d) Trigonal bipyramidal – [Fe(NH3)6]2+,[CuCl4]2–
Answer
D
Question. A coordination compound CrCl3⋅4H2O gives white precipitate of AgCl with AgNO3. The molar conductance of the compound corresponds to two ions. The structural formula of the compound is
(a) [Cr(H2O)4Cl3]
(b) [Cr(H2O)3Cl3]H2O
(c) [Cr(H2O)4Cl2]Cl
(d) [Cr(H2O)4Cl]Cl2
Answer
C
Question. The correct IUPAC name of the coordination compound K3[Fe(CN)5NO] is
(a) potassium pentacyanonitrosylferrate(II)
(b) potassium pentacyanonitroferrate(III)
(c) potassium nitritopentacyanoferrate(IV)
(d) potassium nitritepentacyanoiron(II).
Answer
A
Question. Which of the following complexes will have tetrahedral shape?
(a) [PdCl4]2–
(b) [Pd(CN)4]2–
(c) [Ni(CN)4]2–
(d) [NiCl4]2–
Answer
D
Question. The lowest value of paramagnetism is shown by
(a) [Co(CN)6]3–
(b) [Fe(CN)6]3–
(c) [Cr(CN)6]3–
(d) [Mn(CN)6]3–
Answer
A
Question. When excess of aqueous KCN solution is added to an aqueous solution of copper sulphate, the complex [Cu(CN)4]2– is formed. On passing H2S gas through this solution no precipitate of CuS is formed because
(a) sulphide ions cannot replace CN– ions
(b) [Cu(CN)4]2– does not give Cu2+ ion in the solution
(c) sulphide ions from H2S do not form complexes
(d) sulphide ions cannot replace sulphate ions from copper sulphate solution.
Answer
B
Question. Which of the following has largest paramagnetism?
(a) [Cr(H2O)6]3+
(b) [Fe(H2O)6]2+
(c) [Cu(H2O)6]2+
(d) [Zn(H2O)2]2+
Answer
B
Question. Which of the following does not depict the correct name of the compound?
(a) K2[Zn(OH)4] : Potassium tetrahydroxozincate(II)
(b) [Co(NH3)5CO3]Cl : Pentaammine carbonatochlorocobaltate(III)
(c) Na3[Co(NO2)6] : Sodium hexanitrocobaltate(III)
(d) K3[Cr(CN)6] : Potassium hexacyanochromate(III)
Answer
B
Question. When aqueous solution of potassium fluoride is added to the blue coloured aqueous CuSO4 solution, a green precipitate is formed. This observation can be explained as follows.
(a) On adding KF, H2O being weak field ligand is replaced by F– ions forming [CuF4]2– which is green in colour.
(b) Potassium is coordinated to [Cu(H2O)4]2+ ion present in CuSO4 and gives green colour.
(c) On adding KF, Cu2+ are replaced by K+ forming a green complex.
(d) Blue colour of CuSO4 and yellow colour of KI form green colour on mixing.
Answer
A
Question. Which of the following ligands form a chelate?
(a) Acetate
(b) Oxalate
(c) Cyanide
(d) Ammonia
Answer
B
Question. The ligand N(CH2CH2NH2)3 is
(a) bidentate
(b) tridentate
(c) tetradentate
(d) pentadentate.
Answer
C
Question. Hexacyano complexes of metals in their +2 oxidation state are usually yellow while the corresponding hexaaqua compounds are often blue or green. This is so because
(a) hexacyano complexes absorb orange or red light thus appear yellow while hexaaqua complexes absorb indigo thus appear yellow
(b) hexacyano complexes absorb indigo thus appearing yellow while hexaaqua complexes absorb orange or red light thus appear blue or green
(c) hexacyano complexes absorb yellow light while hexaaqua complexes absorb blue light
(d) CN– ions are yellow in colour while aqua ions are blue or green in colour.
Answer
B
Question. A coordination compound X gives pale yellow colour with AgNO3 solution while its isomer Y gives white precipitate with BaCl2. Two compounds are isomers of CoBrSO4⋅5NH3. What could be the possible formula of X and Y?
(a) X = [Co(NH3)5SO4]Br, Y = [Co(NH3)5Br]SO4
(b) X = [Co(NH3)5Br]SO4, Y = [Co(NH3)5SO4]Br
(c) X = [Co(NH3)5Br(SO4)], Y = [CoBr(SO4)(NH3)5]
(d) X = [Co(Br)5NH3]SO4, Y = [CoBr(SO4)]NH3
Answer
A
Question. Which of the following descriptions about [FeCl6]4– is correct about the complex ion?
(a) sp3d, inner orbital complex, diamagnetic
(b) sp3d2, outer orbital complex, paramagnetic
(c) d2sp3, inner orbital complex, paramagnetic
(d) d2sp3, outer orbital complex, diamagnetic
Answer
B
Question. Ammonia acts as a very good ligand but ammonium ion does not form complexes because
(a) NH3 is a gas while NH4+ is in liquid form
(b) NH3 undergoes sp3 hybridisation while NH4+ undergoes sp3d hybridisation
(c) NH4+ ion does not have any lone pair of electrons
(d) NH4+ ion has one unpaired electron while NH3 has two unpaired electrons.
Answer
C
Question. CuSO4⋅5H2O is blue in colour while CuSO4 is colourless due to
(a) presence of strong field ligand in CuSO4⋅5H2O
(b) due to absence of water (ligand), d-d transition are not possible in CuSO4
(c) anhydrous CuSO4 undergoes d-d transitions due to crystal field splitting
(d) colour is lost due to loss of unpaired electrons.
Answer
B
Question. If a ligand is weak, the complex will be high spin while if the ligand is strong then the complex will be low spin. Here few complexes are listed:
I. [Cr(H2O)6]2+
II. [CoCl4]2–
III. [Fe(H2O)6]2+
IV. [Mn(H2O)6]2+
V. [Ni(CO)4]
VI. [Ni(CN)4]2–
The complexes which have zero magnetic moment are.
(a) I and V
(b) II and VI only
(c) III and IV
(d) V and VI only
Answer
D
Question. Among the following compounds which is both paramagnetic and coloured?
(a) K2Cr2O7
(b) [Co(SO4)]
(c) (NH4)2[TiCl6]
(d) K3[Cu(CN)4]
Answer
B